0=-5.25x^2+63x+5

Solution for 0=-5.25x^2+63x+5 equation:

0=-5.25x^2+63x+5

We move all terms to the left:

0-(-5.25x^2+63x+5)=0

We add all the numbers together, and all the variables

-(-5.25x^2+63x+5)=0

We get rid of parentheses

5.25x^2-63x-5=0

a = 5.25; b = -63; c = -5;
Δ = b2-4ac
Δ = -632-4·5.25·(-5)
Δ = 4074
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{4074}}{2*5.25}=\frac{63-\sqrt{4074}}{10.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{4074}}{2*5.25}=\frac{63+\sqrt{4074}}{10.5}
$